How to replace bearing on flywheel of disc chipper?

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NebClimber

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I had a bearing go out on the flywheel of my disc chipper. The flywheel weighs 3,000 pounds. Anybody ever replace one themselves? If so, how do you keep the flywheel centered as you put the new bearing on?

Steven
 
You might be money ahead to have a shop do this one.

I haven't had to do one of these repairs, but have been in the shop of our Morbark dealer.

They weld lift ring on the disc to lift it out of the housing, then set the disc back in and grind the lift ring off or torch most of it off, then grind.

Most bearings for chippers have to pressed off and pressed back on. This isn't something that can be done in a garage, takes a well equipped shop to do an operation like this.

My two penny input for what it is worth.

Larry
 
Have to agree send this one to a shop that specializes in chipper repair. Might cost a few $$$ but the safety issue of getting it in right and balanced is worth the repair cost.
 
If you can get the flywheel out of the chipper first you can save a bundle at the machine shop. We weld a ring to the disk as per Ax-man's post and use the engine hoist to lift it.

Codie
 
I have relaced quite a few bearings and shafts on the model 100 Morbark. Yo need to loosen bearing and slide out a bit on shaft and then I use a chain in hole where blades bolts on and left out with front end loader. When I change shafts I take to machine shop for $20 and they press out old shaft. Hope this helps
 
Nebclimber, I don't have anything to add but I do have a question. What chipper do you have? The 3000 lb disc boggles my mind. My Olathe has the largest disc diameter I have seen and when I did the math for its disc I came up with 800lbs.
 
Now you guys have me curious as to what my disc would weigh, should I have to do a repair like this.

Stumper what formula did you use???

I'll take a guess at it and you can make the corrections, it has been a loooong time since this guy was in school and math wasn't one of my best subjects.

Let's try this.


dia. of disc x 3.14 x thickness of disc = cu. in of total disc x weight of cu. in of steel in disc = total weight of disc

What would a cu. in of steel weigh or a cu. ft. of steel weigh if you were to convert it to cu. ft.????

Larry
 
You need to do Radius x Radius X3.14 (pi r squared) to get your area. Steel varies slightly according to alloy content but about 416 lbs per cubic foot.
 
The answer to the following question is usually quite alarming:

How many cubic feet can you put in a 5 gallon bucket?
 
Glen...

Although I haven't tried, I'm would guess you can fit as many as 20 cuban feet in a 5 gallon bucket. Getting them to walk is another problem, but you didn't say whether the cubans had to walk...
 
Originally posted by Stumper
You need to do Radius x Radius X3.14 (pi r squared) to get your area. Steel varies slightly according to alloy content but about 416 lbs per cubic foot.

PI x radius squared only gives you the surface area. To get the volume you also need to multiply by the thickness. If your measurements are in inches you'll need to convert to cubic feet to use the 416lb. per cubic foot for steel.

This should give you a fairly accurate estimate. The cut outs for the knives would probably offset the spindle.
 
It's all moot... any given object you REALLY need to lift will be twice as heavy as the equipment you have on hand will handle.
 
That's what I'd meant by alarming.  Visualizing it, you'd think "I could drop a cubic foot in there, maybe two" but a cubic foot is 1728 cubic inches while 5 gallons is 231 × 5 = 1155.  That's little more than 1/8 cubic foot for a gallon paint can.  Sure doesn't seem like it sitting there...

Round peg and square hole kind of thing.

Glen
 
Glen, could you please re-size your post? It's taking too long to download...

Neb, take it to a shop. You'll be GLAD you did.
 
Here's another easy formula.

Use Pi*Dia*Dia/4 *thickness * 0.283
(same as): Pi*Radius*Radius*t*0.283

Diameter and thickness ought to be in your manual somewhere.

Every MFR puts them in for specs.
 
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