Math Question About Cants & Roundwood

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Gypo Logger

Timber Baron
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If an 8" cant has 64 sq. inches, how many square inches does a 10" round log have? A 10 inch log is about 31 inches in circ., and an 8" cant is 32" if measured distance on all four sides. So what is the equation for sq" of a cylinder on the face of the round log? And how does an 8" cant relate to a 10" dia. log volume wise?
What confuses me is that an 8" cant is about as big as a 10" dia. log if measured distance around, but I know I got lost in the math somewhere, so please straighten me out if you can.
Thanks in advance,
John
 
Thanks Roger and Sedanman, that was the answer I was looking for. So if an 8x8 has 64 sq.", and a 10" log has 78. 675 sq. ", and I made a conservative cut in 2.45 sec., in a 10" log, then that means I won, and I didn't have to go to Dan's to prove it. Thanks again, you bunch of sh!t disturbers! LOL
John
 
yes, but which cuts faster...the 10" round or the 8"square cant?

Or maybe you could use the chainsaw?

If you use a 346xp to cut off your broomsticks, isn't it a pain to sweep out the kitchen when you're done?

Ole Svendsen drives over to the border at International falls and there he asks the officials:
Is it closer to Winnipeg, or by bus?
 
The tooth has the ability to remove the same amount of material no matter the shape square or round. With that being said shape will not make a difference as long as the surface are is the same. If you are just looking at nominal size that is different. A 8 inch round is faster that a 8 inch square.

Bill
 
John,

You forgot to add one factor. You are not cutting square inches, you are cutting cubic inches. Add the width of the kerf to get volume. It makes a difference as the size gets bigger, other factors enter in also such as chip removal, friction loss, length of bar and chain and maintaining rpm's, etc.

Art
 
Another way is if the log is 10 inch diameter is bore times bore times . 7854 so that means 10times 10 times .7854 = 78.54 square inches just another way to skin the cat
 
log area

the simplest formula no matter how you slice it is, pi(3.1415927)*r*r. r = radius or half of diameter. volume of material removed from the kerf, is 3.1415927*radius*radius*width of cut. that is the theoretical volume removed. operator error will add to the kerf. as far as round vs. square, i really dont have an opinion.
ok thats not true, but i wont offer my opinion because i havent spent any time evaluating it.
sam
 
John, while a cant you might be using might actually be square in cross-section, it's pretty rare a round is actually round, right?

Probably "close enough" would be to figure the area of any size "round" is about equal to a "square" with a side 8/9 the diameter.  In reverse, the area of any square is about equal to a circle with a diameter 9/8 the square's side.

8" square equals 9" round, more or less.

Just remember 1<sup>1</sup>/<sub>8</sub> (or <sup>9</sup>/<sub>8</sub>) and the square is smaller.

Glen
 
Thanks for the help with the math.
However, since dia. may be here nor there on a round log and measuring the circ. is more accurate, what is the equation for sq"., if only the circ. is known? To answer my own question would it be:
(circ" divided by pi)x DxD X .7854?
Thanks,
John
 
You're making it too hard on yourself.

Since circumference (C) is already pi*D, and D*D*pi/4 is the area

Then (C/pi)*(C/pi)*pi/4 = area

or simplify

C*C/4/pi = area
 
John, you really should be asking your buddy Doug about these math problems.

Here's a little something to chew on (and it only works for shapes which are perfectly circular).

For a given value circumference, divide it by Pi to find the diameter, divide that by 2 to find the radius, square that and multiply it by Pi to find the area.&nbsp; On my HP48 I can create a simple program to do all that thus (it's "Reverse Polish" language):

&nbsp; <<&nbsp; PI&nbsp; /&nbsp; 2&nbsp; /&nbsp; SQ&nbsp; PI&nbsp; *&nbsp; >>

Then after assigning the program to a button, I can key in a value and press the button to find the area of a circle for which that initial value was the circumference.

Here are some results (circumference on left, area on right):

&nbsp;&nbsp; &nbsp;1&nbsp; &nbsp; 0.07957747
&nbsp; 10&nbsp; &nbsp; 7.95774715
100&nbsp; &nbsp; 795.774715

&nbsp; &nbsp;2&nbsp; &nbsp; 0.31830989
&nbsp; &nbsp;4&nbsp; &nbsp; 1.27323954
&nbsp; &nbsp;6&nbsp; &nbsp; 2.86478898
&nbsp; &nbsp;8&nbsp; &nbsp; 5.09295818

(each of the above left-hand values, when putting each "0" behind them, moves the decimal point to the right two more places, exactly as for "1")



Glen
 

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