Tim,
I just more carefully read your last post and scrutinized the image. You have 1½ × the load accounted for! With the "working end" supporting half the load, the "anchor" end would carry the other <i>half</i> of the load. Fastening either end to the load itself would cause that end to bear <i>none</i> of the burden and the half it had previously carried would be shifted to the other end, which would then carry the <i>full</i> load.
Please look at my "29=30" thread in off-topic (linked earlier in this thread, I think) to see how junk math can cause confusion.
Glen
I just more carefully read your last post and scrutinized the image. You have 1½ × the load accounted for! With the "working end" supporting half the load, the "anchor" end would carry the other <i>half</i> of the load. Fastening either end to the load itself would cause that end to bear <i>none</i> of the burden and the half it had previously carried would be shifted to the other end, which would then carry the <i>full</i> load.
Please look at my "29=30" thread in off-topic (linked earlier in this thread, I think) to see how junk math can cause confusion.
Glen