question for all about hot(racing)chain

[Crofter]

Stumper; yep 14,000 in the cut. piped and modified 260. Would be a lot easier with square wood. Just happened to have a time on 10 round which is close to the same wood. I had observed marks a little less than 1/8 apart on one side of some cookies once and hadnt thought of your way of working it out. I came out with 1/10 inch per chain revolution by working out rpm and number of teeth and cutters etc., and the time. I got .007 thou per cutter(per side) yet the chips do measure the raker depth so figured it is only cutting about 1/5 the time or about 2" cycles.

 

[Crofter]

This is a bit slower than it would be piped. Gypo is the photographer, probably Ed at the throttle.

 

[glens]

Some random thoughts on a Sunday afternoon:

If you can't have a "perfectly" round or rectangular hunk of wood to time cutting, you could cut a kerf-width in from the end so that a kerf-width "cookie" falls.  You could then measure it's displacement of water to determine it's volume.

With a known (averaged, or preferably fixed) drive sprocket rpm and the length of measured time for the cut, you could then determine the average volume of fiber removed per cutter during the cut.

 

[LJS]

Glens, your thinking way to much!

 

[Al Smith]

My ,my ,my ,where is this going?Yes,you can get a piece of robotics to do about anything,except have human responses.In terms of repeatability etc.they are tops.To set up an Asea,or Fanuc robot,to do this kind of measurements,would most likely take a cool half million bucks .In the interest of scientific data,it would be a good option but I kind of like "seat of pants" stuff .If you are talking about data,you could glean a lot of info,using this method,very simply[well,not really simple],but that would take the fun out of it,and the lively conversation .

 

[ozflea]

Hell man talk about brains in overdrive.

 

[thf]

Ya guys that think alot always have the fastes chains LOL

 

[LJS]

Glens........whats the average volume of fiber removed per cutter during that cut? LOL

Could you slow those cuts down a little for us thf?, Glens wants to count the teeth going round. LJS

 

[spacemule]

Chainsawworld, I calculated it out to about a tenth of an inch per revolution of the chain. This in 10 inch round. I have seen the evidence of what a long tooth does. The gouges in the endgrain nearly an eighth of an inch apart. If someone wants to run out the math, I used 14,000 and change rpm, 8 tooth, 60 driver, 10 inch wood, 3 seconds. I am guessing about 2 inches run of cut for a tooth to fill the gullet

That's what I got:

60 drivers / 8 pins = 7.5 engine revolutions per chain revolution

14000 engine rpm / 7.5 chain revolutoins = 1866 2/3 chain rpm

1866 2/3 chain rpm x 3/60 minutes cut time = 93 1/3 chain revolutions to cut the cant.

10" / 93 1/3 chain revolutions = .107142857143" per chain revolution.

Is this the way you figured?

 

[spacemule]

How high are your rakers set? Just guessing, I'd think 1/10" per revolution isn't much, but I've never measured such things.

 

[timberwolf]

Spacemule;
that was my method.

Oops, forgot I was driving Timberwolfs computer,

Crofter

 

[Crofter]

Rakers are close to 35 thou. It seems the concensus that the the cutters dont cut continuously. The chips are pretty close to raker clearance in thickness, so I am guestimating they are cutting about 1/5 of available time on 10 inch wood.