Originally posted by Fish
...beavergirl knows the exact formulae!
Fish, you really shouldn't go on this way. While I'm at a loss to explain why since day one, you have been inexplicably drawn to me, I am sincerely flattered regardless of your inspiration. Someone must caution you, and it pains me greatly to be the messenger, however, you're acting quite irresponsibly with your heart. I fully understand how saying this in front of all your friends might sting strongly, but it must be done. People meet, fall in love, and even marry from introductions on the internet, and although I do believe in the impossible, I just can't see this in our near future. I just don't want you to get hurt. Here's a long distance hug anyway.
As for the technical merits of the question at hand, I should digress and allow the resident physicists on board take over. There was a fascinating discussion over at the commercial tree forums involving how much instantaneous apparent weight would an object of 7-8lbs attain if arrested from a freefall of 48". Wow, and I mean Wow, the math finally equaled 2 advil for myself.
matte' maticas headachious adviliosaurus
But what the hell, nothing ventured, nothing gained, right?
I'd first have to figure out the concentration of Oxygen in normal air. For our sake we'll discount any variances of atmostpheric pressure. This reminds me, in all the world of internet associations I've seen, DB is the only person besides myself who expresses pressure correctly in terms of psia or psig. Amazing how our minds flit and float from one topic to the next faster than any known measure of speed. Something else to ponder. What is the speed of thought when applied to linear distance, linear in its simplest form, discounting the influences of relativity. Anyway back to the "chainsaw" issue.
I'll assume Art's figure of 16% is the mean lower level of oxygen for combustion. The following link gave me 21% as the normal concentration of 0²,
http://www.doc.mmu.ac.uk/aric/eae/Atmosphere/Older/Atmospheric_Gases.html,
which, in 25cf of air = 5.25cf of O². 16% of 25cf = 4cf.
5.25-4=1.25cf of consumed O².
I'm a little wary of stating 1.25 cu ft as John didn't qualify the meaning of consume. Does consume mean, the alteration of free O² into other compounds or the total absolute volume of O atoms which were moved through the saw right down to the last mole? There would be some recycled O atoms as CO during the amortization of ever decreasing O² from 21% to 16%. The other thing he didn't mention was which shelf was the saw sitting on. This is sooper important. CO weighs more than O² and if the saw was at the bottom of the refer, to my mind it would stall before the 16% lower level was reached. See, this is where the likes of Stumper, dbabcock, Joe, hillbilly, CJ-7, ramanujan, and Jock are necessary.
So now that a good spin has spun. I'll quietly back out of the laboratory so the think tank can commence thier forays into the deepest realm of smoked venison.
C-