Hello,
Retired Engineer, and I guess I have thought about the following a bit, and realize I don't understand what happens.
Would like to, so thought I'd post here, and if I appear really dumb, I apologize. Still, asking questions is always the best way to learn.
Have a chainsaw, used mainly for small limbs and brush.
Have never taken down a tree, but was wondering:
Let's say that the tree is assumed for this discussion to be a perfect uniform cylinder.
If so, the weight (vector) then can be considered to go right down the center.
No problem here.
All the how-to felling sites say the front cut, which defines the direction one wants the tree to fall, should be no more than 30 % of the tree diameter deep.
So, the weight vector, being at 50 % of the diameter is then to the rear of this cut.
Then the Back-Cut is made.
Even leaving an inch or two for the "hinge," it seems that the weight vector would still definitely be to the rear of the Hinge.
(it would have to go the 70 % of the diameter forward to meet up with front cut, minus the hinge thickness)
And, thus, the tendency of the tree would be to rotate Backwards, not to the front as desired.
True ? Assume No wedges or ropes to help determine the direction of falling.
This would appear to be true even though there is a large wedge taken out from the front, and just a narrow sawblade width Back-Cut ?
I have no doubt that I am wrong, but what am I missing, please in thinking about this ?
I've looked at a zillion videos and on-line diagrams, but none seem to explain this at all.
Is it that the tree cuts are ALWAYS made to have the tree fall in the direction of its normal leaning ?
And if a different fall direction is required, then one uses wedges, ropes, or some of those other "fancy and technical" cutting techniques ?
Thanks,
Bob