I just have to make a comment on this "torque issue" that I see in many many threads. Torque is a thing invented by car magazines that has totally overtaken peoples minds: Statements like: My car (or chainsaw like we discuss here ) performs so great because it has tons of torque... is totally BS IMO.
What we want for a car to accelerate or a saw to cut fast is high torque on the WHEELS/DRIVE SPROCKET, not in the engine! The only thing that determines the speed of the car / saw / whatever machine you want, is POWER. Now, for those of you that have done some physics it's easily described the following way:
Power = Torque * angular velocity (1)
we also have:
Torque 1 * angular velocity 1 = torque 2 * angular velocity 2 (2)
now, let's say that
Torque 1 = engine torque
Torque 2 = drive sprocket torque
angular velocity 1 = engine rpm
angular velocity 2 = sprocket rpm
Combining (1) and (2) we get:
drive sprocket torque = (engine torque * engine rpm / sprocket rpm) = engine POWER / sprocket rpm !
So what you want is high power and a low transmission. There is a reason why they build F1 cars with high power at high rpms with low transmission..
A Formula 1 engine with 601 HP and 400Nm of torque will hence pull a fully loaded truck up the hill quicker than would the truck engine with 600HP with 2500Nm torque. The reason trucks use 16liters diesel engines is because they will last a bit longer than the F1 engine..
Same goes for chainsaws: A 5,4hp chainsaw will always cut faster than a 5,3hp chainsaw . If the 5,3hp chainsaw has higher torque in it's technincal spec. the only thing that this figure says is: This saw has it's max power at a lower rpm than the 5,4hp saw. But the higher rpm of the 5,4hp saw gives a smaller drive sprocket for the same chain speed (= lower transmission) and consequently the 5,3hp saw will be outcut, regardless of it's torque.
I hope it wasn't too fuzzy, just wanted to clear this out. Drop torque and go for high power!
- Peter
What we want for a car to accelerate or a saw to cut fast is high torque on the WHEELS/DRIVE SPROCKET, not in the engine! The only thing that determines the speed of the car / saw / whatever machine you want, is POWER. Now, for those of you that have done some physics it's easily described the following way:
Power = Torque * angular velocity (1)
we also have:
Torque 1 * angular velocity 1 = torque 2 * angular velocity 2 (2)
now, let's say that
Torque 1 = engine torque
Torque 2 = drive sprocket torque
angular velocity 1 = engine rpm
angular velocity 2 = sprocket rpm
Combining (1) and (2) we get:
drive sprocket torque = (engine torque * engine rpm / sprocket rpm) = engine POWER / sprocket rpm !
So what you want is high power and a low transmission. There is a reason why they build F1 cars with high power at high rpms with low transmission..
A Formula 1 engine with 601 HP and 400Nm of torque will hence pull a fully loaded truck up the hill quicker than would the truck engine with 600HP with 2500Nm torque. The reason trucks use 16liters diesel engines is because they will last a bit longer than the F1 engine..
Same goes for chainsaws: A 5,4hp chainsaw will always cut faster than a 5,3hp chainsaw . If the 5,3hp chainsaw has higher torque in it's technincal spec. the only thing that this figure says is: This saw has it's max power at a lower rpm than the 5,4hp saw. But the higher rpm of the 5,4hp saw gives a smaller drive sprocket for the same chain speed (= lower transmission) and consequently the 5,3hp saw will be outcut, regardless of it's torque.
I hope it wasn't too fuzzy, just wanted to clear this out. Drop torque and go for high power!
- Peter