I have a bunch of tall poplar that are nearing end of life, and are leaning the wrong way to fell normally without putting house, barn, or shed at risk.
Check my calculations:
A 2 foot diameter poplar with have a stump area about 3 square feet. 80 feet tall. Let's assume that the branches make up for the trunk taper and for weight purposes it is a cylinder. 240 cubic feet.
Wet poplar at 40 lbs/cuft gives me a mass of 9600 pounds -- about 5 tons
If it leans 15 degrees, (over estimate) then there is about 25% of that load is in the horizontal direction. 2400 lbs.
I have 150' 3/4" nylon solid braid) rope with a rated breaking strength of 20,000 pounds in new condition, with an eye splice on either end.
My thought is put a messenger line into the crown, draw the rope up and over, bring the eye down, and pass thorugh. Attach the other end to my tractor (Deuzt 55 hp -- weighs about 3 tons)
Coefficient of friction on a tractor tire on firm soil is aobut .5 So maximum force tractor can put on rope is about 3000 lbs.
So use the tractor to tension the rope until wheels start to skid, OR it stretches 8% (Estimate of elastic stretch. I have an inquiry with the rope maker for this number)
My plan was to make the wedge cut first, then tension the rope, then make the back cut.
Is this a reasonable approach?
Thought it was a beaver tree. I have seen chicken wire around big cottonwood in the BC interior parts of the Fraser. Cottonwood is not big on the menu in west Canada. They seem to love the Aspen of the interior though.With a few wedges and a tag on the opposite side it fell where I wanted it too. Beavers been chomping on it for 15 years thats why the base looks like that.
Your math looks good. Just two observations, raise your backcut and your hinge will work better with less tearout, and no need to use a square, just use the sight line on your saw.Time to apply some physics here.
I have been falling some 15+ year old poplars which are up to about 20" in diameter and about 90' tall. Many of them are leaning toward the neighbor's house at up to 7 degrees (I doubt the OP's lean is > 10, and if it is I would have second thoughts). Get an inclinometer. These trees would also hit my house if I 'missed'.
One can easily calculate the needed 'force' to prevent the tree from moving (i.e. pull it back over). Let's provide an example with some real data. See diagram in tree.jpg.
We calculate the moment about the holding wood using the tree mass and a 5/16" chain pulling at only 25' up the tree straight out (I'll correct for this later).
Using extremely conservative values:
- Assuming 18" tree is a perfect cylinder 80' tall.
- Mass, using density of 47 lbs/ft^3 (which was measured with a real chunk of wood) is 6700 lbs (3000 kg).
- Force needed on chain for 7 degree lean is calculated at 5781 N, or 589 kg.
- Force needed with chain angle to ground is 604 kg, or 1331 lb.
- Again, this calculation is very conservative, and I expect less than 1000 lb. is needed.
I just fell one of these trees using a 5/16" chain attached at 25' height pulling with my JD2305. Tractor weight (bare) is ~1500 lbs, but I have extra weight (loader, etc.) of about 1200 lbs. so I am at ~ 2700 lbs.
25' is very low, but it still does not approach the shear strength of the holding wood as long as the lean is not enough to overcome holding wood elasticity. Roughly, poplar/cottonwood has a shear strength of 600-700 psi, so unless you cut your holding wood down to a measly 2 in^2, it will hold. This is yet another reason why a 10+ degree lean is dicey.
If one is to attach a rope at 40', the force needed drops considerably: 811 lbs. At 60': 540 lbs.
Point is this can be done safely if you think about it:
- Cut your notch exact
- Use a large tri-square to verify the fall line by putting it in the notch
- (See picture and tractor in background which was exact intended direction)
- Strap the tree so it won't barber chair on you (see picture)
- The notch cut will have more bearing on the fall direction when pulling it down (not the back cut)
- Don't pull hard until the back cut is almost complete
- You will get some pull-out on the holding wood, but that is OK.
I have 9 trees down and 13 more to go. At $900 per tree for a pro to do it, I am doing OK.
~T
Thanks for the input.Your math looks good. Just two observations, raise your backcut and your hinge will work better with less tearout, and no need to use a square, just use the sight line on your saw.
So does your saw, that's what the black line is for.Thanks for the input.
It's hard to tell from the picture but the back cut on that stump is a good two inches above. I use the tri-square as a second check. Some of these trees have to go exactly where I want or I'm going to hit something that will cause damage. Tri square gives me an exact line.
You said never .Never cut problem trees when it is windy.
Yea, me too unless it is near a home. It is hard to tell someone how to use the wind when it stops in mid cut!! CJYou said never .
I often wait until it's windy to cut problem trees.
That's the problem with giving advice on the net, you're not there and it's difficult to transfer your experience in a book let alone a couple paragraphs.
That cut looks interesting I have been lucky to cut, practice and learn where it doesn't matter where a tree falls. Hats off to the pros and more experienced guys who can direct trees within inches of where they want them to go. I'm not there yet but each tree felled is one more learning experienceThanks for the input.
It's hard to tell from the picture but the back cut on that stump is a good two inches above. I use the tri-square as a second check. Some of these trees have to go exactly where I want or I'm going to hit something that will cause damage. Tri square gives me an exact line.
When I cut trees the wind direction and intensity are determining factors what tree get felled that day.You said never .
I often wait until it's windy to cut problem trees.
That's the problem with giving advice on the net, you're not there and it's difficult to transfer your experience in a book let alone a couple paragraphs.
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